You are given two strings, word1
and word2
. You want to construct a string in the following manner:
- Choose some non-empty subsequence
subsequence1
fromword1
. - Choose some non-empty subsequence
subsequence2
fromword2
. - Concatenate the subsequences:
subsequence1 + subsequence2
, to make the string.
Return the length of the longest palindrome that can be constructed in the described manner. If no palindromes can be constructed, return 0
.
A subsequence of a string s
is a string that can be made by deleting some (possibly none) characters from s
without changing the order of the remaining characters.
A palindrome is a string that reads the same forward as well as backward.
Input: word1 = "cacb", word2 = "cbba" Output: 5 Explanation: Choose "ab" from word1 and "cba" from word2 to make "abcba", which is a palindrome.
Input: word1 = "ab", word2 = "ab" Output: 3 Explanation: Choose "ab" from word1 and "a" from word2 to make "aba", which is a palindrome.
Input: word1 = "aa", word2 = "bb" Output: 0 Explanation: You cannot construct a palindrome from the described method, so return 0.
1 <= word1.length, word2.length <= 1000
word1
andword2
consist of lowercase English letters.
fromfunctoolsimportcacheclassSolution: deflongestPalindrome(self, word1: str, word2: str) ->int: @cachedeflongestSubPalindrome(i: int, j: int) ->int: ifi>j: return0ifi==j: return1ret=max(longestSubPalindrome(i, j-1), longestSubPalindrome(i+1, j)) ifword[i] ==word[j]: ret=max(ret, 2+longestSubPalindrome(i+1, j-1)) returnretword=word1+word2first= [[-1, -1] for_inrange(26)] ret=0foriinrange(len(word1) -1, -1, -1): first[ord(word1[i]) -97][0] =iforiinrange(len(word1), len(word)): first[ord(word[i]) -97][1] =ifori, jinfirst: ifi>=0andj>=0: ret=max(ret, 2+longestSubPalindrome(i+1, j-1)) returnret